solve question 2 of ex 13.3 class 10
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Hey mate..
Hope it helps..!!
@Rêyaañ11
Hope it helps..!!
@Rêyaañ11
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Radius of first sphere = 6 cm
Radius of second sphere = 8 cm
Radius of third sphere = 10 cm
Volume of sphere formed = Sum of Volume of three sphere....
4/3 pi R^3 = 4/3 pi R1^3 + 4/3 pi R2^3 + 4/3 pi R3^3
=> 4/3 pi R^3 = 4/3 pi ( R1^3 + R2^3 + R3^3)
=> R^3 = R1^3 + R2^3 + R3^3
=> R^3 = 6^3 + 8^3 + 10^3
=> R^3 = 216 + 512 + 1000
=> R^3 = 1728
=> R^3 = 12^3
=> R = 12 cm
Radius of new sphere formed = 12 cm
Radius of second sphere = 8 cm
Radius of third sphere = 10 cm
Volume of sphere formed = Sum of Volume of three sphere....
4/3 pi R^3 = 4/3 pi R1^3 + 4/3 pi R2^3 + 4/3 pi R3^3
=> 4/3 pi R^3 = 4/3 pi ( R1^3 + R2^3 + R3^3)
=> R^3 = R1^3 + R2^3 + R3^3
=> R^3 = 6^3 + 8^3 + 10^3
=> R^3 = 216 + 512 + 1000
=> R^3 = 1728
=> R^3 = 12^3
=> R = 12 cm
Radius of new sphere formed = 12 cm
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