Question

Solve question 5 and 6 of Height and distance

Answer 1

[Note :refer the all four attachments for the Explanation ]

$\boxed{\textbf{\large{Answers}}}$

Q5]

➡1) The length of AB = 27.26 cm

2) the distance of the AB from the center c is 6.21 cm

Q6]

➡ height of the tower is 180 metre

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Some information about Q1) and Q2)

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Q1]

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◻ for the first question , first construct the circle and then according to question ,draw a chord AB subtends an angles of 131° at the centre c of the circle

◻Draw a perpendicular from the center of the circle to a chord which devides the chord in two equal parts

◻As shown in the attachment, consider a triangle ACM and from the sin ratio calculate the length of AM, AM = 1/2 AB, AB = 2 AM

◻For finding the value of CM, use cosΦ [ consider the triangle ACM ]

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Q2]

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◻ To find the height of tower ,refer the figure in the attachment, As we know that, tanΦ = opposite side /hypotenuse , as shown in the figure opposite side is the height of a tower

◻ we have given the values of tangents at a different conditions, and also we have the distance between the angles [ on walking towards the tower at a 192 meter the angles changes ]

◻ Compare the ratios of tan (Φ1) and tan(Φ2) , as shown in the attachment then we can get the value of mx

◻As we know 15mx is the value of height, put the value of mx in 15 mx, then finally we can calculate the height of tower.

[Note : Must refer the attachments while reading the information about the questions . ]

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