Question

Solve question 7 plss fast

Answer 1

$p(x) = 4 {x}^{2} + 4 x+ 4 \\ { \alpha }^{2} + { \beta }^{2} = 2u \\ then \\ \alpha + \beta = - 1 \\ \alpha \times \beta = 1 \\ { \alpha }^{2} + { \beta }^{2} = {( \alpha + \beta )}^{2} - 2 \alpha \beta \\ \: \: \: \: \: \: \: \: \: \: \: \: \: = 1 - 2 \\ so \\ { \alpha }^{2} + { \beta }^{2} = - 1$

2u=-1

u=-1/2