Question

solve question no. 130

Answer 1

given ,
maximum possible horizontal range is 400 .
hence,
particle maximum goes in x -axis 0 to 400 m .
if you remember , concept of projectile you see at heighest position velocity of projectile is minimum.
but heighest position in midpoint of Range e.g x =200 m
now ,
maximum possible range means inclination angle is 45 degree .
Due to R =u^2sin2@/g
R ----max sin2@ -----> max
but sin2@ max =1 e.g R =u^2/g -------(1)
so,
@ =45
now y =maximum height =u^2sin^2@/2g
put @ =45 hence, y=u^2/4g =R/4
from equation (1)

y =400/4 =100 m

hence co-ordinate is (200m ,100m)