Solve question no.20 for take brainliest...please.
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now see the line BC if BP AND BQ ARE THE TANGENTS THEN BP=BQ
therefore CQ = BC-BQ
= 11 CM
now if CQ AND CR ARE TANGENTS THEN
CQ=CR
SO CR =11
now in line CD. DR=CD-CR
SO. DR= 14 CM
now join the circle center o to R AND S
NOW AS SD AND RD ARE TANGENTS THE WILL FORM A RIGHT ANGLE
from give angle is equal to 90 we can say it is a square ( all angles are 90, and both tangents are equal and both radius r are equally)
in DOC
as we can assume that height of the triangle is DS as it is and scalen triangle
therefore area of triangle DOC
1/2 * dc* DS
1/2 * 25*14
therefore 175 cm
there fore in the same triangle let us take height as the radius
therefore
1/2 * OR * DC = AREA DOC
1/2 * OR *25 = 175
OR == 175*2/25
OR= 14 CM
therefore radius of the circle is 14 cm
now see the line BC if BP AND BQ ARE THE TANGENTS THEN BP=BQ
therefore CQ = BC-BQ
= 11 CM
now if CQ AND CR ARE TANGENTS THEN
CQ=CR
SO CR =11
now in line CD. DR=CD-CR
SO. DR= 14 CM
now join the circle center o to R AND S
NOW AS SD AND RD ARE TANGENTS THE WILL FORM A RIGHT ANGLE
from give angle is equal to 90 we can say it is a square ( all angles are 90, and both tangents are equal and both radius r are equally)
in DOC
as we can assume that height of the triangle is DS as it is and scalen triangle
therefore area of triangle DOC
1/2 * dc* DS
1/2 * 25*14
therefore 175 cm
there fore in the same triangle let us take height as the radius
therefore
1/2 * OR * DC = AREA DOC
1/2 * OR *25 = 175
OR == 175*2/25
OR= 14 CM
therefore radius of the circle is 14 cm
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brainliest
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