Question

solve Question No. 5 fast

Answer 1

Let the two numbers be x and y.

Given that sum of twice the first and thrice the 2nd is 92.

2x + 3y = 92  ----------- (1)

Given that four times the first exceeds seven times the second by 2.

4x = 7y + 2

4x - 7y = 2   ------------------- (2)


On solving (1)* 2 & (2), we get

4x + 6y = 184

4x - 7y = 2

-------------------

13y = 182

y = 14.


Substitute y = 14 in (1), we get

2x + 3y = 92

2x + 3(14) = 92

2x + 42 = 92

2x = 92 - 42

2x = 50

x = 25.



Therefore the two numbers are 25 and 14.


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