Question

Solve QUESTION No. 8.


thanks ❤️

Answer 1

kx + y = k^2

=> kx + y - k^2 = 0

a1 = k

b2 = 1

c1 = - k^2
______________

x + ky = 1

=> x + ky - 1 = 0

a2 = 1

b2 = k

c2 = - 1

Now,

For infinite solutions,

a1 / a2 = b1 / b2 = c1 / c2

=> k / 1 = 1 / k = k^2 / 1

From (1) and (2), we get

k/1 = 1 /k

=> k^2 = 1

=> k = +1 and - 1 -------(A)

Now,

From (1) and (3), we get

k/1 = k^2 /1

=> k = k^2

=> 1 = k --------(B)

From equation A and B, we can say that there is only one value of k that satisfy the given condition.

Required value of k = 1