Question

solve question no 9 please​

Answer 1

Answer:

the answer is in the picture attavhed

Step-by-step explanation:

pls tell which book and which chapter

Answer 2

Answer:

Step-by-step explanation:

DA = CB [Opp. sides of Rect. are equal]

AE = EB [given]

Now, DA =CA

        AE =EB

        ∠A = ∠B {90°}

∴ΔDAE ≅ ΔCBE (SAS)

∴DE = CE (all parts of a congruent Δ is equal)

∴ΔDEC is iso. Δ