solve question number 11
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hey here is ur answer......
Energy of one photon=hv
h=6.626 ×{10}^{ - 34}
v= 5 ×10 ^{14}
so... E=3.313 × {10}^{ - 19} J/mol
now as we know in one mole we have avgadro no. of photons..
so total Energy...
E=3.313 × {10}^{-19} × 6.02 ×{10}^{23}
= 19.94 ×{10}^{4} J/mol
=199.4 KJ/mol
hope this helps plz mark it brainliest...
Energy of one photon=hv
h=6.626 ×{10}^{ - 34}
v= 5 ×10 ^{14}
so... E=3.313 × {10}^{ - 19} J/mol
now as we know in one mole we have avgadro no. of photons..
so total Energy...
E=3.313 × {10}^{-19} × 6.02 ×{10}^{23}
= 19.94 ×{10}^{4} J/mol
=199.4 KJ/mol
hope this helps plz mark it brainliest...
yashg05090:
dhyan SE dekh th leta Bhai comment SE pehle maine answer 10 ki power mein express kiya tha....now u can c I wrote the way u expected.
I hope now it's ok with u
jadda tez na ban
tera answer phla 2×10 raise to the power 5 aaya tha
19.94 ×10^4 ko 1.994 × 10^5 likh sakte hain....n that is approx 2×10^5 Mr yes.
*tez
ok
yeah....
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Answered by
3
Answer:
HI MATE.
Energy = number of photons * energy in one photon
= n h v
= 6.023 * 10²³ * 6.626 * 10⁻³⁴ * 5 * 10¹⁴Joules
= 199.54 kJoules
Hope it helps you mate.
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