Question

solve question number 14...in the simplest way u can...

Answer 1

let no's be a,a+d,a+2d

as sum of zeroes = 12

3a +3d = 12

a+d = 4

also product of zeroes = 28

a( a+d) ( a+d+d) = 28

put a+d = 4

a( 4) (4+d) = 28

a = 4-d

a( 4+d) = 7

16 - d.d = 7

d.d = 9
d = 3

a = 4-d = 4-3 = 1

zeroes are 1,4,7