solve question number 14...in the simplest way u can...
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let no's be a,a+d,a+2d
as sum of zeroes = 12
3a +3d = 12
a+d = 4
also product of zeroes = 28
a( a+d) ( a+d+d) = 28
put a+d = 4
a( 4) (4+d) = 28
a = 4-d
a( 4+d) = 7
16 - d.d = 7
d.d = 9
d = 3
a = 4-d = 4-3 = 1
zeroes are 1,4,7
as sum of zeroes = 12
3a +3d = 12
a+d = 4
also product of zeroes = 28
a( a+d) ( a+d+d) = 28
put a+d = 4
a( 4) (4+d) = 28
a = 4-d
a( 4+d) = 7
16 - d.d = 7
d.d = 9
d = 3
a = 4-d = 4-3 = 1
zeroes are 1,4,7
alia5523:
thanks a lot...
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