Question

solve question number 15

Answer 1

Let the number of coins of Rs1, Rs2 and Rs5 be x, y and z respectively.
Now,
$x + y + z = 160$
$1.x + 2.y + 3.z = 300$
$z=3y$
Putting z=3y in the above two equations, we get:
$x + 4y = 160$
$x + 11y = 300$
Solving these, we get:
$y = 20$
Thus,
$x = 80$
Therefore,
$z = 60$
Therefore, number of Rs1 coins, Rs2 coins and Rs5 coins are 80, 20 and 60 respectively.
Hope you find this useful.