solve question number 15 it's argent and elaborate this question explain
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piya46:
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Object height (h) = 1cm
Object distance (u) = -15 cm [Object distance and focal length are taken negative in Concave mirror;New Cartesian Sign Convension]
Focal length (f) = -10 cm
We know, 1/v + 1/u = 1/f [Mirror formula]
Therefore, 1/v = 1/f - 1/u
1/v = 1/(-10) - 1/(-15)
1/v = 1/(-10) + 1/15 [(-) x (-) = (+)]
1/v = 5/(-150) [Cross-multiplying]
v = -150/5 = -30 cm
m = h'/h = -v/u [Formula of magnification]
Therefore,h' = -vh/u
h' = -(-30) x (1)/(-15)
h' = -2 cm
(b)It is because water has less refractive index and we know that refractive index is inversely proportional to the speed of light.
Object distance (u) = -15 cm [Object distance and focal length are taken negative in Concave mirror;New Cartesian Sign Convension]
Focal length (f) = -10 cm
We know, 1/v + 1/u = 1/f [Mirror formula]
Therefore, 1/v = 1/f - 1/u
1/v = 1/(-10) - 1/(-15)
1/v = 1/(-10) + 1/15 [(-) x (-) = (+)]
1/v = 5/(-150) [Cross-multiplying]
v = -150/5 = -30 cm
m = h'/h = -v/u [Formula of magnification]
Therefore,h' = -vh/u
h' = -(-30) x (1)/(-15)
h' = -2 cm
(b)It is because water has less refractive index and we know that refractive index is inversely proportional to the speed of light.
yes
app ko kaise pta chla ki real image bn rhi h
mujhe ye nhi pta chata ki real image bn rhi ki Virtual bn rhi h
plz tell me and help me
app ko kaise pta chla ki object distant hai
i am so confused plz help now
kya kh rhe ho smjh me nhi aa rha h
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