Question

solve question number
•5(ii)
•11(ii)

Answer 1

5.

(ii) 32x^2 - 2(x - 4)^2

     = 32x^2 - 2(x^2 + 16 - 8x)

     = 32x^2 - 2x^2 - 32 + 16x

     = 30x^2 + 16x - 32

     = 2(15x^2 + 8x - 16)

     = 2(15x^2 - 12x + 20x - 16)

     = 2(3x(5x - 4) + 4(5x - 4))

     = 2(5x - 4)(3x + 4).



11.

(ii) 64a^3b^3 - 27

    = (4ab)^3 - (3)^3

We know that a^3 - b^3 = (a - b)(a^2 + ab + b^2)

    = (4ab - 3)((4ab)^2 + (4ab)(3) + (3)^2)

    = (4ab - 3)(16a^2b^2 + 12ab + 9)




Hope this helps!