Question

solve questions 3 of ml aggarwal ex 6​

Answer 1

Answer:

what

Step-by-step explanation:

Answer 2

$let \: the \: two \: no.be \\ \\ x \: and \: y \: \\ a.t.q \: of \: first \: statememt \\ x + y = 43 \\ multiplying \: eqn \: (1) \: by \: \\ 3we \: get \: \\ 3x + 3y = 129 \: \: \: - (3) \\ 2x - 3y = 36 \: \: \: \: - (2) \\ 5x = 165 \\ \\ x = \frac{165}{5} \\ x = 33 \\ \\ substituting \: the \: value \: of \: x \\ in \: eq \: (1) \\ 33 + y = 43 \\ y = 43 - 33 \\ y = 10 \\ \\ hence \: the \: two \: no. \\ are \: 33 \: and \: 10$

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