Question

solve root2x - root3y = 0 and root5x + root2y =0

Answer 1

$\sqrt{2} x - \sqrt{3} y = 0 - - - (1) \\ \sqrt{5} x + \sqrt{2} y = 0 - - - (2)$
$(1) \times \sqrt{2} + (2) \times \sqrt{3} \: \: gives \\ (2 + \sqrt{15} )x = 0 \\ x = 0 \\ substituting \: \: in \: \: (1) \\ - \sqrt{3} y = 0 \\ y = 0$
Therefore solution is (0,0)

Answer 2

Step-by-step explanation:

see above ans. I have written detaily