Question

Solve root3 sinx+COSx=2​

Answer 1

Answer:

Step-by-step explanation:

sqrt(3)sinx+cosx=1

sqrt(3)sinx=1-cosx

3sin^2x=1-2cosx+cos^2x -- square both sides

3(1-cos^2x)=1-2cosx+cos^2x -- Pythagorean relationship

4cos^2x-2cosx-2=0 -- clear parantheses and collect

2cos^2x-cosx-1=0

(2cosx+1)(cosx-1)=0

cosx=-1/2 or cosx=1

Hope it helps!

Please mark it as brainliest.

Answer 2

Answer:

Not possible

Step-by-step explanation:

Sinx + cosx can never be equal to 2