Solve sin(A-B)/cosAcosB+sin(B-C)/cosbcosc+sin(C-A)/cosCcosA
Answers
Answered by
5
Answer:
=0
Step-by-step explanation;
sin(a-b )=sina cosb -cosa sinb
same formula for others also.
sinAcosB/cosAcosB-cosAsinB/cosAcosb +sinBcosC/cosCcosB-cosBsinC/cosBcosC +sinCcosA/cosCcosA-cosCsinA/cosCcosA=
tanA-tanB+tanB-tanC+tanC-tanA
=0
arunima180901:
welcome
Similar questions