solve sin(sin^-1(1÷5)+cos^-1x)=1
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Hey there !!!!
sin(sin⁻¹1/5+cos⁻¹x)=1
sin⁻¹1/5+cos⁻¹x=sin⁻¹1
But sinπ/2=1
⇒sin⁻¹1=π/2P An inverse trignometry - sin⁻¹1/5+cos⁻¹x=π/2--------Equation 1 sin⁻¹t+cos⁻¹t=π/2 So, sin⁻¹ 1/5+cos⁻¹x=π/2 Therefore value of x will be 1/5.
hope this helped you !!!
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