Math, asked by powerstr1234, 4 months ago

solve:sin²x-5sinx+4=0​

Answers

Answered by manoj7k1993
1

Step-by-step explanation:

 {sin}^{2} x - 5sin \: x + 4 \\  {sin}^{2} x - 4sin \: x - sin \: x + 4 \\ sinx(sinx - 4) - 1(sinx - 4) \\ (sinx - 4)(sinx - 1) \\

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