Question

solve sin2x dy/dx=y+tanx

Answer 1

Step-by-step explanation:

sin2x dy/dx=y+tanx

Using, linear order differential equation,

$\frac{dx}{dy}$ + P(x) dx = Q(x)

Solving we get,

Hence

⇒ y . (1 / cosec 2x+cot 2x ) =  1/3 ($\sqrt[3/2]{tanx}$) + c