Math, asked by manishkr32, 1 year ago

Solve. Sin3x_Sinx=4Cos^2x_2

Answers

Answered by kishankumar81

Sin 3x - Sin x

=2Cos (3x + x / 2) X sin (3x - x / 2)

=2Cos 2x . Sin x

=2(2 Cos2 x - 1) Sin x

=(4Cos2 x - 2) Sin x

manishkr32: X ka value nikalna hai

kishankumar81: o i see

kishankumar81: but x ka value nahi nikle ga

kishankumar81: Sin 3x - Sin x

=2Cos (3x + x / 2) X sin (3x - x / 2)

=2Cos 2x . Sin x

=2(2 Cos2 x - 1) Sin x

=(4Cos2 x - 2) Sin x

manishkr32: niklega

manishkr32: aap question nhi samjhe

kishankumar81: can you tell me

manishkr32: ya

manishkr32: can i send you the pic

kishankumar81: ya

Answered by prem235

Step-by-step explanation:

Sin 3x - Sin x

=2Cos (3x + x / 2) X sin (3x - x / 2)

==2Cos 2x . Sin x

=2(2 Cos^x - 1) Sin x

=(4Cos^2x - 2) Sin x

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