Solve. Sin3x_Sinx=4Cos^2x_2
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Answered by
3
Sin 3x - Sin x
=2Cos (3x + x / 2) X sin (3x - x / 2)
=2Cos 2x . Sin x
=2(2 Cos2 x - 1) Sin x
=(4Cos2 x - 2) Sin x
=2Cos (3x + x / 2) X sin (3x - x / 2)
=2Cos 2x . Sin x
=2(2 Cos2 x - 1) Sin x
=(4Cos2 x - 2) Sin x
manishkr32:
X ka value nikalna hai
o i see
but x ka value nahi nikle ga
Sin 3x - Sin x
=2Cos (3x + x / 2) X sin (3x - x / 2)
=2Cos 2x . Sin x
=2(2 Cos2 x - 1) Sin x
=(4Cos2 x - 2) Sin x
=2Cos (3x + x / 2) X sin (3x - x / 2)
=2Cos 2x . Sin x
=2(2 Cos2 x - 1) Sin x
=(4Cos2 x - 2) Sin x
niklega
aap question nhi samjhe
can you tell me
ya
can i send you the pic
ya
Answered by
1
Step-by-step explanation:
Sin 3x - Sin x
=2Cos (3x + x / 2) X sin (3x - x / 2)
==2Cos 2x . Sin x
=2(2 Cos^x - 1) Sin x
=(4Cos^2x - 2) Sin x
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