Question

solve solve for X and Y : 47x+31y=63, 31x+47y=15​

Answer 1

Here Is Your Ans ⤵

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47x + 31y = 63 ⬅equation 1

31x + 47y = 15 ⬅equation 2

multiply equation 1 by 31 and equation 2 by 47

We get

1457x + 961y = 1953 ⬅equation 3

1457x + 2209y = 705 ⬅equation 4

subtract equation 3 and 4

We get ↘

=> -1248y = 1248

=> y = -1

put The value of Y in equation 3

=> 1457x + 961(-1) = 1953

=> X = 2914 / 1457 = 2

Hence , you the value of X is 2 and Y is -1

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Answer 2

Answer:

7x+31y=63(eqn 1)

31x+47y=15(eqn 2)

adding both eqn,we get

78x+78y=78

dividing this eqn by 78,we get

x+y=1 (be it eqn 3)

subtracting eqn 1 and eqn 2,we get

16x-16y=48

dividing this eqn by 16, we get

x-y=3(be it eqn 4)

using elimination method for eqn 3and eqn4

x+y=1

x-y=3

2x=4

x=2

putting value of x in x+y=1,by solving we get

y=-(negative)1

therefore

x=2

y=-1

Step-by-step explanation: