Question

solve solve solve solve​

Answer 1

$\huge{\underline{\underline{Answer\::-}}}$

$\underline{\underline{Given\::-}}$

$3^{x+3} + \dfrac{3^{x+4}}{3} = 162$

$\underline{\underline{Solving\::-}}$

$3^{x+3} + \dfrac{3^{x+4}}{3} = 162$

=> $3^{x+3} + 3^{x+4} ÷ 3 = 162$

=> $3^{x+3} + 3^{x+4 - 1} = 162$

=> $3^{x+3} + 3^{x+3} = 162$

=> $2 \times 3^{x+3} = 162$

=> $3^{x+4} = 81$

=> $3^{x+4} = 3^4$

Then as base are same

=> x + 4 = 4

=> x = 4 - 4

=> x = 0

So value of x = $\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{0}}}}}}}}$

Hope it helps

Answer 2

so,x=1

hey mate here is answer.

I hpe that it will help you.

please mark as brainliest.