Math, asked by akshayaakshaya184, 1 year ago

Solve sqrt 2x+1+sqrt 3x+2=sqrt5x+3​

Answers

Answered by avinash0303
6

Step-by-step explanation:

Tiger was unable to solve based on your input

sqrt(5x-3)-sqrt(2x-1)=sqrt(3x-2)

Too many square root symbols, max 2 allowed

.. V

sqrt(5x-3)-sqrt(2x-1)=sqrt(3x-2)

How to use Tiger's Radical Equation Solver:

(A) Inputing the square root:

Either using the square root symbol: √(x+20)=x

Or: sqrt(x+20)=x

In either case, the parenthesis "( )" are mandatory

(B) Types of radical equations that Tiger solves:

(1) sqrt(x-2)=sqrt(x/2)+1

(2) sqrt(x+5)=sqrt(5x)

(3) 6sqrt(x+5)=30

(4) sqrt(x/5)=x-120

(C) Syntax:

(1) Max 2 sqrts in an equation

(2) sqrt(x)/sqrt(5) is not acceptable use sqrt(x/5) instead

(3) Parenthesis not allowed except for around sqrt arguments

(D) Questions ? Bugs ? Please use the discussion area

Program Execution Terminated

Tiger was not able to solve for your input:sqrt(5x-3)-sqrt(2x-1)=sqrt(3x-2)

Submit your own solution!

Answered by guduruvenkatesh92
1

Answer:

sqrt(5x-3)-sqrt(2x-1)=sqrt(3x-2)

Too many square root symbols, max 2 allowed

.. V

sqrt(5x-3)-sqrt(2x-1)=sqrt(3x-2)

(A) Inputing the square root:

Either using the square root symbol: √(x+20)=x

Or: sqrt(x+20)=x

In either case, the parenthesis "( )" are mandatory

(1) sqrt(x-2)=sqrt(x/2)+1

(2) sqrt(x+5)=sqrt(5x)

(3) 6sqrt(x+5)=30

(4) sqrt(x/5)=x-120) Max 2 sqrts in an equation

(2) sqrt(x)/sqrt(5) is not acceptable use sqrt(x/5) instead

(3) Parenthesis not allowed except for around sqrt arguments

I hope this is a correct answer

Please mark as a brain list

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