Math, asked by Itshadow, 1 year ago

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Answered by prabhhere
1

Area of Rhombus (Diagonal Formula)

 =  \frac{diagonal1 \times diagonal2}{2}

 =    \frac{6x {y}^{2} z \:  \times 8 {x}^{2}yz }{2}

 =  \frac{48 {x}^{3} {y}^{3}  {z}^{2}  }{2}

 = 24 {x}^{3}  {y}^{3}  {z}^{2} sq. units

Answered by akshatcomm10aug
1

Answer:

24x^3y^3z^2

steps-(6xy^2z*8x^2yz)/2

=(48x^3y^3z^2)/2

=24x^3y^3z^2

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