Chemistry, asked by lakshyaanand025, 2 months ago

SOLVE STEP BY STEP!
When 20 kJ of heat is removed from 1.2 kg of ice originally at -15°C, its new temperature is
Please solve step by step
Answer is -23C
S(ice)=2100j/kg/C

Answers

Answered by jigarmansuri786

3

Answer:

Explanation:

Here we use the relation, Q=m×s×Δθ

Substituting, Q=50.4kJ=50400J

m=1.2kg

Q=m×s×Δθ

s=Qm×Δθ=504001.2×20=2100 J kg−1

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