Solve:
Take out the value of x&y.
Attachments:
Answers
Answered by
1
Answer:
2x+1+35y−3=12 (given
⇒213(2x+1)+7(5y−3)=12
⇒6x+3+35y−21=252
⇒6x+35y−18=252
⇒6x+35y=270
⇒6x=270−35y
⇒x=6250−35y
23x+2−94y+3=13 (given )
⇒189(3x+2)−2(4y+3)=13
⇒27x+18−8y−6=234
⇒27x−8y+12=234
⇒27x−8y=222..(1)
Substituting x=6270−35y in (1) we get
27(6270−35y)−8y=
Similar questions