Solve tan5theta.tan3theta=1
Anonymous:
prove that?
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tan 3θ=1/tan5θ
(0<θ<2π)
tan 3θ=cot5θ
tan 3θ=tan(π/2 -5θ)
3θ=π/2 -5θ, 3π/2 -5θ, 5π/2 -5θ,7π/2 -5θ, .....31π/2 -5θ,
8θ=π/2 , 3π/2 , 5π/2 ,7π/2 , .....31π/2
θ=π/16 , 3π/16 , 5π/16 ,7π/16 , .....31π/16
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