Question

solve
$- 1 + 64m {2}$
by identity​

Answer 1

Answer:

the answer is (8m+1)(8m-1)

Step-by-step explanation:

$- 1 + 64 {m}^{2} \\ = 64 {m }^{2} - (1) {}^{2} \\ \\ using \: the \: identity \\ {x}^{2} - {y}^{2} = (x + y)( x - y) \\ =64 {m}^{2} - ( {1}^{2} ) \\ {(8m ){}^{2} - ( {1})^{2} }^{} \\ = (8m + 1)(8m - 1)$