solve
![2 \sin {}^{2} x + 2 \ \sqrt{2} \: sinx - 3 = 0 2 \sin {}^{2} x + 2 \ \sqrt{2} \: sinx - 3 = 0](https://tex.z-dn.net/?f=2+++%5Csin+%7B%7D%5E%7B2%7D+x+%2B+2+%5C+%5Csqrt%7B2%7D++++%5C%3A+sinx+-+3+%3D+0)
Answers
Answered by
1
Answer:
45
Step-by-step explanation:
that's the answer for your question
Attachments:
![](https://hi-static.z-dn.net/files/d1a/1d111b8e2758da8c81f37d4f4eb9a43b.jpg)
Similar questions