Solve:
![2 {x}^{2} - 5x + 3 = 0 2 {x}^{2} - 5x + 3 = 0](https://tex.z-dn.net/?f=2+%7Bx%7D%5E%7B2%7D++-+5x+%2B+3+%3D+0)
Answers
Answered by
2
Step-by-step explanation:
2x^2-5x+3=0
2x^2-2x-3x+3=0
2x(x-1)-3(x-1)=0
(x-1)(2x-3)=0
x=1 or x=3/2
Hope it helps you.
Answered by
0
2x^2-5x+3=0
2x^2-6x-x+3=0
2x(x-3)-1(x-3)=0
(2x-1)(x-3)=0
2x-1=0. x-3=0
X=1/2. X=3
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