Question

Solve:-
$(3q + 1) {}^{3}$
Using identity?​

Answer 1

Formula used:-

(a+b)³=a³+b³+3a²b+3ab²

Now:-

(3q+1)³

=>(3q)³ + 1³ + 3 (3q)² (1) + 3 (3q) (1)²

=>27q³ + 1 + 3 (9q²) + 9q

=>27q³+ 1 + 27q² + 9q

(3q + 1)³ = 27q³ + 1 + 27q² + 9q.

Answer 2

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To Find :-

$➪ \: {(3q + 1)}^{3}$

Identity :-

$➪ \: {(a + b)}^{3} = {a}^{3} + 3 {a}^{2} b + 3a {b}^{2} + {b}^{3}$

Solution :-

By applying the formula,

( Considering a = 3q and b = 1 )

$➪ \: {(3q + 1)}^{3} = {(3q)}^{3} + 3 {(3q)}^{2} (1) + 3(3q)( {1})^{2} + {1}^{3} \\ \\ \large \boxed{= 27 {q}^{3} + 27 {q}^{2} + 9q + 1}$

@SweetestBitter