Question

solve
$3x { }^{2} - 2 \sqrt{6} x + 2$
find the value of x

Answer 1

Hey

Here is your answer

3x² - 2√6x +2 = 0
3x² -√6x - √6x + 2 = 0
√3x(√3x - √2) - √2(√3x - √2) = 0
(√3x - √2)(√3x - √2) = 0
√3x - √2 = 0
x = √2 / √3
√3x - √2 = 0
x = √2 / √3

Hope it helps you!

Answer 2

Hello User !!!

p(x) = 3x² - 2√6x + 2

x = [ - b ± √(b² - 4ac ) ] / 2a

x = [ - ( - 2√6 ) ± √( 24 - 24 ) / 2 × 3

x = ( 2√6 ± 0 ) / 6

x = √6 / 3

x = √2 × √3 / 3

x = √2 / √3

Hope it helps