Question

Solve :
$4 {y}^{2} + \frac{6}{ {y}^{2} } = 11$
[Hint : Substitute x for y?]​

Answer 1

Answer:

Value of y is 1

Step-by-step explanation:

4y² + $\frac{6}{y^{2}}$=11

=> 4x + $\frac{6}{x}$=11                                 [Let y² = x]

=> $\frac{4x+x + 6}{x}$=11

=> $\frac{5x + 6}{x}$=11

=> 5x + 6 = 11x

=>-11x + 5x = -6

=> -6x = -6

=> x = $\frac{-6}{-6}$

=>x = 1                                        

=>y² = 1                                        [as y² = 1]

=>y = $\sqrt{1}$

=>y = 1

Ans:- Value of y is 1