Question

solve:-${7x}^{2} + 5x + 3$______

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Answer 1

By using quadratic formula

$\implies \underline{ \boxed{\bf x = \dfrac{ - b\pm \sqrt{ {b}^{2} - 4ac} }{2a}}}$

Here

a = 7

b = 5

c = 3

Substitute values in formula

$\begin{gathered}\implies \sf x = \dfrac{ - 5\pm \sqrt{ {5}^{2} - 4 \times 7 \times 3} }{2 \times 7} \\ \\ \implies \sf x = \dfrac{ - 5\pm \sqrt{25 - 63} }{21} \\ \\ \implies \sf x = \dfrac{ - 5\pm \sqrt{ - 35} }{21}\end{gathered}$

Talking +ve sign

$\implies \sf x = \dfrac{ - 5 - \sqrt{ 35} }{21}$

Taking - ve sign

$\implies \sf x = \dfrac{ - 5 + \sqrt{ 35} }{21}$

Answer 2

$\small\mathrm\orange{Answer}$

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• This formula is known as " Sridharacharya Formula "

• The values of a, b, c are the co-effecients of 7x² + 5x + 3

• Therefore, a = 7 , b = 5 , c = 3