Question

solve:

$f(px) = {p}^{3} {x}^{2} - {p}^{2} x - 4p$
If
$f(0) = - 20$
​

Answer 1

Answer: p = 5

Step-by-step explanation:

Let's first find the actual f(0) by remainder theorem.

$=p^{3}(0)^{2} -p^{2}(0)-4p\\ =0-0-4p\\=-4p$

Therefore,

$-20=-4p\\\\=>p=\frac{-20}{-4} \\\\=>p=5$

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