What are the zeros of the quadratic function f(x) = 6x2 + 12x – 7?
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Answer:
x=1+2√6i6,1−2√6i6
Explanation:
Solve:
−6x2+12x−7=0 is a quadratic equation in standard form: ax2+bx+c, where a=−6, b=12, and c=−7.
The quadratic formula can be used to solve this equation.
x=−b±√b2−4ac2a
Substitute the given values into the formula.
x=−12±√122−4×−6×−72×−6
x=−12±√144−168−12
x=−12±√−24−12
Factor −24.
x=−12±√2×2×2×3i−12
x=−12±2√6i−12
Simplify by dividing by −12.
x=1±2√6i6
Solutions for x.
x=1+2√6i6,1−2√6i6
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x=1+2√6i6,1−2√6i6
Explanation:
Solve:
−6x2+12x−7=0 is a quadratic equation in standard form: ax2+bx+c, where a=−6, b=12, and c=−7.
The quadratic formula can be used to solve this equation.
x=−b±√b2−4ac2a
Substitute the given values into the formula.
x=−12±√122−4×−6×−72×−6
x=−12±√144−168−12
x=−12±√−24−12
Factor −24.
x=−12±√2×2×2×3i−12
x=−12±2√6i−12
Simplify by dividing by −12.
x=1±2√6i6
Solutions for x.
x=1+2√6i6,1−2√6i6
hyyy mate mark as brainlist
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