Question

Solve:–

$\frac{2}{5x} - \frac{5}{3x} = \frac{1}{15}$
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Answer 1

Answer:

$\frac{2}{5x} - \frac{5}{3x} = \frac{1}{15} \\ \frac{2 \times 3}{5x \times3} = \frac{6}{15x} \\ \frac{5 \times 5}{3x \times 5} = \frac{25}{15x} \\ \frac{6 - 25}{15x} = \frac{1}{5} \\ \frac{ - 19}{15x} = \frac{1}{15} \\ \frac{ - 19}{x} = \frac{15}{15} \\ x = - 19 \\ hope \: it \: helps \: you \: dear$

Answer 2

Answer:

Analysis→

Here we're an equation that $\displaystyle\rm\dfrac{2}{5x}-\dfrac{5}{3x}=\dfrac{1}{15}$ .And we can see that their denominators is not equal. So we've to make their denominators equal by taking their LCM. And then we can simply find the answer.

Given→

• $\displaystyle\rm\dfrac{2}{5x}-\dfrac{5}{3x}=\dfrac{1}{15}$

To Find→

Solution for the given equation.

Answer→

$\displaystyle\rm\rightarrow\dfrac{2}{5x}-\dfrac{5}{3x}=\dfrac{1}{15}$

$\displaystyle\rm\rightarrow\dfrac{3\times2}{15x}-\dfrac{5\times5}{15x}=\dfrac{1}{15}[LCM(3x,5x)=15x]$

$\displaystyle\rm\rightarrow\dfrac{6}{15x}-\dfrac{25}{15x}=\dfrac{1}{15}$

$\displaystyle\rm\rightarrow\dfrac{(6-25)}{15x}=\dfrac{1}{15}$

$\displaystyle\rm\rightarrow\dfrac{-19}{15x}=\dfrac{1}{15}$

Cross Multiplication Method→

$\displaystyle\rm\rightarrow\dfrac{-19}{15x}=\dfrac{1}{15}$

$\displaystyle\rm\rightarrow{-19\times15}=1\times15x$

$\displaystyle\rightarrow\rm\dfrac{-19\times15}{15}=x$

$\displaystyle\rm\rightarrow\dfrac{-19\times{\cancel{15}}}{\cancel{15}}=x$

$\displaystyle\rm\rightarrow{-19=x}$

$\displaystyle\rm\rightarrow{x=-19}$

${\boxed{\boxed{\rightarrow{\rm{x=-19\checkmark}}}}}$

☞ Hence the value of x is -19, which is the required answer.

HOPE IT HELPS.