Question

Solve [tex] P^{2} - 5P + 6 = 0, where P =\frac{dy}{dx} [\tex]

Answer 1

Given:$p^{2}-5p+6=0$

we have to find the value of $p.$

$p^{2}-5p+6=0$

$p^{2}-3p-2p+6=0$

$p(p-3)-2(p-3)=0$

$p-3=0,p-2=0$

$p=3,p=2.$

The values of $p$ are $3,2.$