Math, asked by Chintoo2709, 1 year ago

Solve
 {x}^{2}  -  \sqrt{3} x - 18 = 0

Answers

Answered by Afzal999
2

b {}^{2}  - 4ac =  \sqrt{3 {}^{2} }  - 4 \times 1 \times  - 18 \\  = 3 + 72 \\  = 75 \\  \frac{ -  \sqrt{3}  +  -  \sqrt{75} }{2}  \\  =
Similar questions