Question

Solve $x^2-(x+1) = 0$ for $x$

Answer 1

x² - x - 1 = 0
a = 1, b = -1, c = -1

$x = \frac{-b \pm \sqrt{b^2-4ac} }{2a}\\ \\ x = \frac{1 \pm \sqrt{1+4} }{2}\\ \\ x = \frac{1 \pm \sqrt{5} }{2}\\ \\ x = \frac{1 + \sqrt{5} }{2}\ \ \ \ and\ \ \ \ \frac{1 - \sqrt{5} }{2}$

Answer 2

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Solve:-

$x^2-(x+1) = 0$ for $x$

$\LARGE{\red{\boxed{\purple{\underline{\orange{\mathtt{Solution:↓}}}}}}}$

x² - x - 1 = 0

a = 1, b = -1, c = -1

$\begin{gathered}x = \frac{-b \pm \sqrt{b^2-4ac} }{2a}\\ \\ x = \frac{1 \pm \sqrt{1+4} }{2}\\ \\ x = \frac{1 \pm \sqrt{5} }{2}\\ \\ x = \frac{1 + \sqrt{5} }{2}\ \ \ \ and\ \ \ \ \frac{1 - \sqrt{5} }{2} \end{gathered}$