Question

solve
$( {x}^{2} -y x{}^{2} )dy \: + (y {}^{2} + xy {}^{2} )dx = 0$

Answer 1

$= d {x}^{2} y - d {x}^{2}y + dx {y}^{2} + d {x}^{2} {y}^{2}$
$= dxy(x + - xy + y + xy)$
$= dxy(x + y)$

Answer 2

Answer:

this is your answer bro