Math, asked by siddarth29, 1 year ago

solve
 {y} {y}^{1}  + 25x = 0

Answers

Answered by rakeshmohata
2
Hope u like my process
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 =  > \bf y y_{1} + 25x = 0 \\  \\  =  >  y\frac{dy}{dx}  =  - 25x \\  \\  =  > ydy =  - 25xdx \\  \\  =  >  \int \: ydy =  - 25 \int \: xdx \\  \\  =  >  \frac{ {y}^{2} }{2}  =  - 25 \frac{ {x}^{2} }{2}  + c \\  \\  =  >   \bf \: {y}^{2}  + 25 {x}^{2}  = c
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Hope this is ur required general solution
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Proud to help you
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