Question

solve
${y} {y}^{1} + 25x = 0$

Answer 1

Hope u like my process
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$= > \bf y y_{1} + 25x = 0 \\ \\ = > y\frac{dy}{dx} = - 25x \\ \\ = > ydy = - 25xdx \\ \\ = > \int \: ydy = - 25 \int \: xdx \\ \\ = > \frac{ {y}^{2} }{2} = - 25 \frac{ {x}^{2} }{2} + c \\ \\ = > \bf \: {y}^{2} + 25 {x}^{2} = c$
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