solve th following equation by using cramers rule =
2x+y+z=7
3x-y-z=-2
x+2y-3z=-4
Answers
Answered by
0
Step-by-step explanation:
2x−y+2z=4
3x+2y+3z=16
x+3y+2z=12
Δ=
∣
∣
∣
∣
∣
∣
∣
∣
∣
2
3
1
−1
2
3
2
3
2
∣
∣
∣
∣
∣
∣
∣
∣
∣
=2(4−9)+1(6−3)+2(9−2)
=−10+3+14=7
Δ
x
=
∣
∣
∣
∣
∣
∣
∣
∣
∣
4
16
12
−1
2
3
2
3
2
∣
∣
∣
∣
∣
∣
∣
∣
∣
=4(4−9)+1(32−36)+2(48−24)
=−20−4+48=24
Δ
y
=
∣
∣
∣
∣
∣
∣
∣
∣
∣
2
3
1
4
16
12
2
3
2
∣
∣
∣
∣
∣
∣
∣
∣
∣
=2(32−36)−4(6−3)+2(36−16)
=−8−12+40=20
Δ
z
=
∣
∣
∣
∣
∣
∣
∣
∣
∣
2
3
1
−1
2
3
4
16
12
∣
∣
∣
∣
∣
∣
∣
∣
∣
=2(24−36)+1(36−16)+4(9−2)
=−48+20+28=0
∴x=
Δ
Δ
x
,y=
Δ
Δ
y
,z=
Δ
Δ
z
⟹x=
7
24
,y=
7
20
,z=0
Similar questions