Solve that AU(BnC)=(AUB)n(AUC)
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I proved this with the help of Venn-Diagram
Hope this was helpful
Hope this was helpful
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Since, A∪B = The total region Covered by both set A and set B
And, A∩B = The common region bounded by set A and set B.
With help of this, we can make the diagram,
By the below diagram 1 ,
= The total region of A and B∩C
And, by the diagram 2,
= The total region of A and B∩C
Thus, AU(B∩C) = (A∪B) ∩ (A∪C)
Hence, proved.
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