Math, asked by AnmolChaudhary, 1 year ago

Solve this question plzzz....

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Answered by Doubt1
0
the diagonal of a rhombus bisect the angle angle intersect at 90 also bisect each other
using all these properties
DOC =90
DCO= 30
CDO= 60
now use trignometry
sin 30 and sin60
take their ratio the answer will come
Answered by madanmohan1
0
we know that the diagonals of Rhombus bisect each other so,
AO=OC, OD=OB
AC/BD=2(DO)/2 (OC) =OD/OC....... (1)
angle OCD=30°
Angle COD=60°
angle DOC=90°
now, in triangle, DOC
tan30°=1/root 3
OD/OC=1/root 3
From (1),
AC/BD=1/root 3
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