Math, asked by mm9944355, 4 months ago

solve that problems​

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Answers

Answered by vipashyana1
1

Answer:

1)x²+x-6

=x²+3x-2x-6

=(x²+3x)-(2x-6)

=x(x+3)-2(x+3)

=(x+3)(x-2)

2)x²-x-2

=x²-2x+x-2

=(x²-2x)+(x-2)

=x(x-2)+1(x-2)

=(x-2)(x+1)

3)x²+3x-18

=x²+6x-3x-18

=(x²+6x)-(3x-18)

=x(x+6)-3(x+6)

=(x+6)(x-3)

4)x²-5x-6

=x²-2x-3x-6

=(x²-2x)-(3x-6)

=x(x-2)-3(x-2)

=(x-2)(x-3)(not sure)

5)x²+4x+4

=x²+2x+2x+4

=(x²+2x)+(2x+4)

=x(x+2)+2(x+2)

=(x+2)(x+2)

=(x+2)²

7)y²+5y+6

=y²+2y+3y+6

=(y²+2y)+(3y+6)

=y(y+2)+3(y+2)

=(y+2)(y+3)

8)y²+6y+8

=y²+4y+2y+8

=(y²+4y)+(2y+8)

=y(y+4)+2(y+4)

=(y+4)(y+2)

9)p²+2p-8

=p²+4p-2p-8

=(p²+4p)-(2p-8)

=p(p+4)-2(p+4)

=(p+4)(p-2)

Answered by zipathan939
3

Answer:

Hello sis how are you ?

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