Question

Solve that sum if you Can..Good Explanation will be mark as brainliest...

Answer 1

hey there,

Let ‘a’ be the first term of the AP and ‘d’ be the common difference

S1 = (n/2)[2a + (n – 1)d] --- (1)

S2 = (2n/2)[2a + (2n – 1)d] = n[2a + (n – 1)d] --- (2)

S3 = (3n/2)[2a + (3n – 1)d] --- (3)

Consider the RHS: 3(S2 – S1)

Substitute the values of S2 and S1 and simplify to get the LHS.    

Hope this helps!

Answer 2

Here is Your Answer

Hope it Helps

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