solve the 21th no. please
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p(x) = x³+6x²+12x+16
= putting x= ±1,±2,±3,±4,±5 etc ......
putting x= 1
p(1) = (1)³ + 6(1)² + 12(1) + 16
= 1 + 6 +12 + 16 = 35
= 35 ≠ 0
so x-1 is not factor of p(x)
putting x= (-4)
p(-4) = (-4)³ + 6(-4)² + 12(-4) + 16
= -64 + 96 - 48 + 16 = 0
0=0
so x+4 is a factor of p(x)
then divide p(x) by x+4
you got the answer
= putting x= ±1,±2,±3,±4,±5 etc ......
putting x= 1
p(1) = (1)³ + 6(1)² + 12(1) + 16
= 1 + 6 +12 + 16 = 35
= 35 ≠ 0
so x-1 is not factor of p(x)
putting x= (-4)
p(-4) = (-4)³ + 6(-4)² + 12(-4) + 16
= -64 + 96 - 48 + 16 = 0
0=0
so x+4 is a factor of p(x)
then divide p(x) by x+4
you got the answer
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