solve the 4th and 6th problems
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the amount borrowed is the principle.
Therefore, P=₹12000
Rate=6%
Time=2 years
Now, its asked the difference of the S.I amount and C.I amount; therefore, first we have to find the S.I.
S.I.= 12000x6x2
**************
100
= ₹1440
Therefore,
Amount= ₹(12000 + 1440)
= ₹ 13440
Now to find C.I. Amount;
For 1st year;
C.l.= 12000x6x1
*************
100
= ₹720
Amount=₹(12000 + 720)
=₹12720
For 2nd year;
C.I.= 12720x6x1
*************
100
= ₹763.2
Amount= ₹(12720 + 732.5)
= ₹13452.5
Therefore the difference is;
=C.I. - S.I.
=₹(13452.5 - 13440)
=₹12.5
Therefore, the extra amount to be paid would be ₹12.5
Hope I helped you out!
Therefore, P=₹12000
Rate=6%
Time=2 years
Now, its asked the difference of the S.I amount and C.I amount; therefore, first we have to find the S.I.
S.I.= 12000x6x2
**************
100
= ₹1440
Therefore,
Amount= ₹(12000 + 1440)
= ₹ 13440
Now to find C.I. Amount;
For 1st year;
C.l.= 12000x6x1
*************
100
= ₹720
Amount=₹(12000 + 720)
=₹12720
For 2nd year;
C.I.= 12720x6x1
*************
100
= ₹763.2
Amount= ₹(12720 + 732.5)
= ₹13452.5
Therefore the difference is;
=C.I. - S.I.
=₹(13452.5 - 13440)
=₹12.5
Therefore, the extra amount to be paid would be ₹12.5
Hope I helped you out!
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